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Chemistry Textbook

Thermal Energy, Temperature and Heat

By the end of this section, you will be able to:

  • Define and distinguish specific heat and heat capacity, and describe the physical implications of both

  • Perform calculations involving heat, specific heat, and temperature change

Thermal energy is kinetic energy associated with the random motion of atoms and molecules. Temperature is a quantitative measure of “hot” or “cold.” When the atoms and molecules in an object are moving or vibrating quickly, they have a higher average kinetic energy (KE), and we say that the object is “hot.” When the atoms and molecules are moving slowly, they have lower average KE, and we say that the object is “cold” (Figure 5.4). Assuming that no chemical reaction or phase change (such as melting or vaporizing) occurs, increasing the amount of thermal energy in a sample of matter will cause its temperature to increase. And, assuming that no chemical reaction or phase change (such as condensation or freezing) occurs, decreasing the amount of thermal energy in a sample of matter will cause its temperature to decrease.

Two molecular drawings are shown and labeled a and b. Drawing a is a box containing fourteen red spheres that are surrounded by lines indicating that the particles are moving rapidly. This drawing has a label that reads “Hot liquid.” Drawing b depicts another box of equal size that also contains fourteen spheres, but these are blue. They are all surrounded by smaller lines that depict some particle motion, but not as much as in drawing a. This drawing has a label that reads “Cold liquid.”
Figure 5.4 (a) The molecules in a sample of hot water move more rapidly than (b) those in a sample of cold water.

Heat

Heat (q) is the transfer of thermal energy between two bodies at different temperatures. Heat flow (a redundant term, but one commonly used) increases the thermal energy of one body and decreases the thermal energy of the other. Suppose we initially have a high temperature (and high thermal energy) substance (H) and a low temperature (and low thermal energy) substance (L). The atoms and molecules in H have a higher average KE than those in L. If we place substance H in contact with substance L, the thermal energy will flow spontaneously from substance H to substance L. The temperature of substance H will decrease, as will the average KE of its molecules; the temperature of substance L will increase, along with the average KE of its molecules. Heat flow will continue until the two substances are at the same temperature (Figure 5.5). Matter undergoing chemical reactions and physical changes can release or absorb heat. A change that releases heat is called an exothermic process while a reaction or change that absorbs heat is an endothermic process.

Three drawings are shown and labeled a, b, and c, respectively. The first drawing labeled a depicts two boxes, with a space in between and the pair is captioned “Different temperatures.” The left hand box is labeled H and holds fourteen well-spaced red spheres with lines drawn around them to indicate rapid motion. The right hand box is labeled L and depicts fourteen blue spheres that are closer together than the red spheres and have smaller lines around them showing less particle motion. The second drawing labeled b depicts two boxes that are touching one another. The left box is labeled H and contains fourteen maroon spheres that are spaced evenly apart. There are tiny lines around each sphere depicting particle movement. The right box is labeled L and holds fourteen purple spheres that are slightly closer together than the maroon spheres. There are also tiny lines around each sphere depicting particle movement. A black arrow points from the left box to the right box and the pair of diagrams is captioned “Contact.” The third drawing labeled c, is labeled “Thermal equilibrium.” There are two boxes shown in contact with one another. Both boxes contain fourteen purple spheres with small lines around them depicting moderate movement. The left box is labeled H and the right box is labeled L.
Figure 5.5 (a) Substances H and L are initially at different temperatures, and their atoms have different average kinetic energies. (b) When they contact each other, collisions between the molecules result in the transfer of kinetic (thermal) energy from the hotter to the cooler matter. (c) The two objects reach “thermal equilibrium” when both substances are at the same temperature and their molecules have the same average kinetic energy.

Heat Capacity

Historically, energy was measured in units of calories (cal). A calorie is the amount of energy required to raise one gram of water by 1 degree C (1 kelvin). However, this quantity depends on the atmospheric pressure and the starting temperature of the water. The ease of measurement of energy changes in calories has meant that the calorie is still frequently used. The Calorie (with a capital C), or large calorie, commonly used in quantifying food energy content, is a kilocalorie. The SI unit of heat, work, and energy is the joule. A joule (J) is defined as the amount of energy used when a force of 1 newton moves an object 1 meter. It is named in honor of the English physicist James Prescott Joule. One joule is equivalent to 1 kg m2/s2, which is also called 1 newton–meter. A kilojoule (kJ) is 1000 joules. To standardize its definition, 1 calorie has been set to equal 4.184 joules.

We now introduce two concepts useful in describing heat flow and temperature change. The heat capacity (C) of a body of matter is the quantity of heat (q) it absorbs or releases when it experiences a temperature change (ΔT) of 1 degree Celsius (or equivalently, 1 kelvin):

C = q Δ T C=qΔT

Heat capacity is determined by both the type and amount of substance that absorbs or releases heat. It is therefore an extensive property—its value is proportional to the amount of the substance.

For example, consider the heat capacities of two cast iron frying pans. The heat capacity of the large pan is five times greater than that of the small pan because, although both are made of the same material, the mass of the large pan is five times greater than the mass of the small pan. More mass means more atoms are present in the larger pan, so it takes more energy to make all of those atoms vibrate faster. The heat capacity of the small cast iron frying pan is found by observing that it takes 18,150 J of energy to raise the temperature of the pan by 50.0 °C:

Csmall pan=18,140 J50.0°C=363J/°CCsmall pan=18,140 J50.0°C=363J/°C

The larger cast iron frying pan, while made of the same substance, requires 90,700 J of energy to raise its temperature by 50.0 °C. The larger pan has a (proportionally) larger heat capacity because the larger amount of material requires a (proportionally) larger amount of energy to yield the same temperature change:

Clarge pan=90,700 J50.0°C=1814J/°CClarge pan=90,700 J50.0°C=1814J/°C

The specific heat capacity (c) of a substance, commonly called its “specific heat,” is the quantity of heat required to raise the temperature of 1 gram of a substance by 1 degree Celsius (or 1 kelvin):

c = q m Δ T c=qmΔT

Specific heat capacity depends only on the kind of substance absorbing or releasing heat. It is an intensive property—the type, but not the amount, of the substance is all that matters. For example, the small cast iron frying pan has a mass of 808 g. The specific heat of iron (the material used to make the pan) is therefore:

ciron=18,140 J(808 g)(50.0°C)=0.449 J/g °Cciron=18,140 J(808 g)(50.0°C)=0.449 J/g °C

The large frying pan has a mass of 4040 g. Using the data for this pan, we can also calculate the specific heat of iron:

ciron=90,700 J(4040 g)(50.0°C)=0.449 J/g °Cciron=90,700 J(4040 g)(50.0°C)=0.449 J/g °C

Although the large pan is more massive than the small pan, since both are made of the same material, they both yield the same value for specific heat (for the material of construction, iron). Note that specific heat is measured in units of energy per temperature per mass and is an intensive property, being derived from a ratio of two extensive properties (heat and mass). The molar heat capacity, also an intensive property, is the heat capacity per mole of a particular substance and has units of J/mol °C (Figure 5.6).

The picture shows two black metal frying pans sitting on a flat surface. The left pan is about half the size of the right pan.
Figure 5.6 Because of its larger mass, a large frying pan has a larger heat capacity than a small frying pan. Because they are made of the same material, both frying pans have the same specific heat. (credit: Mark Blaser)

water has a relatively high specific heat (about 4.2 J/g °C for the liquid and 2.09 J/g °C for the solid)); most metals have much lower specific heats (usually less than 1 J/g °C).

The specific heat of a substance varies somewhat with temperature. However, this variation is usually small enough that we will treat specific heat as constant over the range of temperatures that will be considered in this chapter. Specific heats of some common substances are listed in Table 5.1.

Specific Heats of Common Substances at 25 °C and 1 bar

Substance

Symbol (state)

Specific Heat (J/g °C)

helium

He(g)

5.193

water

H2O(l)

4.184

ethanol

C2H6O(l)

2.376

ice

H2O(s)

2.093 (at −10 °C)

water vapor

H2O(g)

1.864

nitrogen

N2(g)

1.040

air

 

1.007

oxygen

O2(g)

0.918

aluminum

Al(s)

0.897

carbon dioxide

CO2(g)

0.853

argon

Ar(g)

0.522

iron

Fe(s)

0.449

copper

Cu(s)

0.385

lead

Pb(s)

0.130

gold

Au(s)

0.129

silicon

Si(s)

0.712

Table 5.1 Specific Heats of common substances at 25 °C

If we know the mass of a substance and its specific heat, we can determine the amount of heat, q, entering or leaving the substance by measuring the temperature change before and after the heat is gained or lost:

q=(specific heat)×(mass of substance)×(temperature change)q=c×m×ΔT=c×m×(TfinalTinitial)q=(specific heat)×(mass of substance)×(temperature change)q=c×m×ΔT=c×m×(TfinalTinitial)

In this equation, c is the specific heat of the substance, m is its mass, and ΔT (which is read “delta T”) is the temperature change, TfinalTinitial. If a substance gains thermal energy, its temperature increases, its final temperature is higher than its initial temperature, TfinalTinitial has a positive value, and the value of q is positive. If a substance loses thermal energy, its temperature decreases, the final temperature is lower than the initial temperature, TfinalTinitial has a negative value, and the value of q is negative.

EXAMPLE 5.6
Measuring Heat

A flask containing 8.0 ×× 102 g of water is heated, and the temperature of the water increases from 21 °C to 85 °C. How much heat did the water absorb?

Solution:

To answer this question, consider these factors:

  • the specific heat of the substance being heated (in this case, water)
  • the amount of substance being heated (in this case, 8.0 × 102 g)
  • the magnitude of the temperature change (in this case, from 21 °C to 85 °C).

The specific heat of water is 4.184 J/g °C, so to heat 1 g of water by 1 °C requires 4.184 J. We note that since 4.184 J is required to heat 1 g of water by 1 °C, we will need 800 times as much to heat 8.0 × 102 g of water by 1 °C. Finally, we observe that since 4.184 J are required to heat 1 g of water by 1 °C, we will need 64 times as much to heat it by 64 °C (that is, from 21 °C to 85 °C).

This can be summarized using the equation:

q=c×m×ΔT=c×m×(TfinalTinitial)q=c×m×ΔT=c×m×(TfinalTinitial)
=(4.184J/g°C)×(8.0x102g)×(8521)°C=(4.184J/g°C)×(8.0x102g)×(64)°C=210,000 J(=2.1×102kJ)=(4.184J/g°C)×(8.0x102g)×(8521)°C=(4.184J/g°C)×(8.0x102g)×(64)°C=210,000 J(=2.1×102kJ)

Because the temperature increased, the water absorbed heat and q is positive.

Check Your Learning:

How much heat, in joules, must be added to a 5.07 ×× 104 J iron skillet to increase its temperature from 25 °C to 250 °C? The specific heat of iron is 0.449 J/g °C.

Answer:

5.07 ×× 104 J

EXAMPLE 5.7
Heat transfer

What quantity of heat is transferred when a 150.0 g block of iron metal is heated from 25.0°C to 73.3°C? What is the direction of heat flow? Specific heat of iron is 0.108 cal/g•K

Solution:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the iron is 73.3°C and the initial temperature is 25.0°C,

ΔT is as follows: ΔT = Tfinal − Tinitial = 73.3°C − 25.0°C = 48.3°C = 48.3K
(Note: Change in temperature will be the same magnitude on the Kelvin and celcius scale (ie. 1°C ΔT = 1K ΔT )
Proof: 73.3°C = 346.1K;   25.0°C = 298.0 K;   ΔT = 346.1K − 298.0K = 48.3K)

The mass is given as 150.0 g, and the specific heat of iron is 0.108 cal/g•K.

Substitute the known values into heat = mcΔT and solve for amount of heat:

heat=150.0 g ×  0.108 calg K   ×  48.3K =782 cal 

Note how the gram and K units cancel algebraically, leaving only the calorie unit, which is a unit of heat. Because the temperature of the iron increases, energy (as heat) must be flowing into the metal as reflected from the positive value of heat obtained in the calculation.

Check Your Learning:

Determine the heat capacity (in cal/g K) of a substance if 23.6 g of the substance loses 199 cal of heat when its temperature changes from 37.9°C to 20.9°C. 

Answer:

0.496 cal/g.K

Footnotes

  • 1 Francis D. Reardon et al. “The Snellen human calorimeter revisited, re-engineered and upgraded: Design and performance characteristics.” Medical and Biological Engineering and Computing 8 (2006)721–28, http://link.springer.com/article/10.1007/s11517-006-0086-5.

 

Key Equations:

C = q Δ T C=qΔT c = q m Δ T c=qmΔT

Conversion factor for change in temperature:   1°C  ∆T  =  1K  ∆T